If all the words with or without meaning made | vedclass

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Question

(C) The letters in the word $NAGPUR$ are $A, G, N, P, R, U$. Total letters = $6$. Total arrangements = $6! = 720$.Words starting with $A$: $5! = 120$

Vedclass · Accepted Answer

$NRAPGU$

Vedclass · Answer

(C) The letters in the word $NAGPUR$ are $A, G, N, P, R, U$. Total letters = $6$. Total arrangements = $6! = 720$.Words starting with $A$: $5! = 120$ words.Words starting with $G$: $5! = 120$ words.Total words so far = $120 + 120 = 240$.Words starting with $NA$: $4! = 24$ words.Words starting with $NG$: $4! = 24$ words.Words starting with $NP$: $4! = 24$ words.Total words so far = $240 + 24 + 24 + 24 = 312$.We need the $315^{	ext{th}}$ word. The remaining words start with $NR$.Words starting with $NRA$: $3! = 6$ words.$313^{	ext{th}}$ word: $NRAGPU$$314^{	ext{th}}$ word: $NRAGUP$$315^{	ext{th}}$ word: $NRAPGU$

If all the words with or without meaning made using all the letters of the word $NAGPUR$ are arranged as in a dictionary,then the word at $315^{\text{th}}$ position in this arrangement is:

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