If an alpha particle with energy $7.7 \text{ MeV}$ is bombarded on a thin gold foil, the closest distance from the nucleus it can reach is . . . . . . $\text{m}$. (Atomic number of gold $= 79$ and $\frac{1}{4 \pi \epsilon_0} = 9 \times 10^9$ in $SI$ units)

  • A
    $2.95 \times 10^{-14}$
  • B
    $2.95 \times 10^{-16}$
  • C
    $3.85 \times 10^{-16}$
  • D
    $3.85 \times 10^{-14}$

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