If an ammeter is connected in parallel to a circuit,it is likely to be damaged due to excess

In the adjoining circuit diagram,the readings of the ammeter and voltmeter are $2 \, A$ and $120 \, V$,respectively. If the value of $R$ is $75 \, \Omega$,then the voltmeter resistance will be (in $\Omega$):

$A$ galvanometer with a resistance of $12 \,\Omega$ gives full-scale deflection when a current of $3 \, mA$ is passed. It is required to convert it into a voltmeter which can read up to $18 \, V$. The resistance to be connected is ............... $\Omega$.

$A$ galvanometer has a $50$ division scale. The battery has no internal resistance. It is found that there is a deflection of $40$ divisions when $R = 2400\,\Omega$. The deflection becomes $20$ divisions when the resistance taken from the resistance box is $4900\,\Omega$. Then we can conclude:

To make the magnetic field radial in a moving coil galvanometer:

$A$ galvanometer has a resistance of $50 \ \Omega$ and it allows a maximum current of $5 \ mA$. It can be converted into a voltmeter to measure up to $100 \ V$ by connecting in series a resistor of resistance: (in $\Omega$)