If an endothermic reaction is non-spontaneous | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a reaction to be spontaneous,the Gibbs free energy change $\Delta G = \Delta H - T\Delta S$ must be negative $(\Delta G < 0)$.Given that the r

Vedclass · Accepted Answer

$\Delta H$ and $\Delta S$ both are $+ve$

Vedclass · Answer

(B) For a reaction to be spontaneous,the Gibbs free energy change $\Delta G = \Delta H - T\Delta S$ must be negative $(\Delta G Given that the reaction is endothermic,$\Delta H > 0$ (positive).At the freezing point of water $(T = 273 \ K)$,the reaction is non-spontaneous,meaning $\Delta G > 0$,so $\Delta H > T\Delta S$.At the boiling point of water $(T = 373 \ K)$,the reaction becomes feasible (spontaneous),meaning $\Delta G Since $\Delta H$ is positive,for $\Delta G$ to become negative as $T$ increases,$\Delta S$ must also be positive. Thus,both $\Delta H$ and $\Delta S$ are positive.

If an endothermic reaction is non-spontaneous at the freezing point of water and becomes feasible at its boiling point,then:

Similar Questions

Which of the following conditions results in a spontaneous chemical reaction?

If for a certain reaction $\Delta_{r} H$ is $30 \; kJ \; mol^{-1}$ at $450 \; K$,the value of $\Delta_{r} S$ (in $J \; K^{-1} \; mol^{-1}$) for which the same reaction will be spontaneous at the same temperature is

The standard enthalpy of the decomposition of $N_2O_4$ to $NO_2$ is $58.04 \, kJ$ and standard entropy of this reaction is $176.7 \, J/K$. The standard free energy change for this reaction at $25 \, ^oC$ is $..... \, kJ$

Gibbs free energy $G$,enthalpy $H$ and entropy $S$ are interrelated as in

For a spontaneous change,free energy change $\Delta G$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module