If an ion M^{3+} contains 10 electrons and 14 | vedclass

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Question

(A) The ion $M^{3+}$ is formed by the loss of $3$ electrons from a neutral atom $M$.Since the ion contains $10$ electrons, the number of electrons in

Vedclass · Accepted Answer

Atomic number = $13$, Mass number = $27$

Vedclass · Answer

(A) The ion $M^{3+}$ is formed by the loss of $3$ electrons from a neutral atom $M$.Since the ion contains $10$ electrons, the number of electrons in the neutral atom $M$ is $10 + 3 = 13$.In a neutral atom, the number of electrons is equal to the number of protons, which defines the atomic number.Therefore, the atomic number of element $M$ is $13$.The mass number is the sum of the number of protons and neutrons.Mass number = $	ext{Atomic number} + 	ext{Number of neutrons} = 13 + 14 = 27$.

If an ion $M^{3+}$ contains $10$ electrons and $14$ neutrons, what are the atomic number and mass number of the element $M$?

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