If an object is placed at $A$ $(OA > f)$,where $f$ is the focal length of the lens,the image is found to be formed at $B$. $A$ perpendicular is erected at $O$ and $C$ is chosen on it such that the angle $\angle BCA$ is a right angle. Then the value of $f$ will be

  • A
    $AB/OC^2$
  • B
    $(AC)(BC)/OC$
  • C
    $OC^2/AB$
  • D
    $(OC)(AB)/(AC+BC)$

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