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(B) The mean free path $\lambda$ of a gas molecule is given by the formula: $\lambda = \frac{1}{\sqrt{2} \pi d^2 n}$,where $d$ is the diameter of the

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Infinite

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(B) The mean free path $\lambda$ of a gas molecule is given by the formula: $\lambda = \frac{1}{\sqrt{2} \pi d^2 n}$,where $d$ is the diameter of the molecule and $n$ is the number density of the molecules.As the diameter $d$ of the gas molecule approaches zero $(d 	o 0)$,the denominator $\sqrt{2} \pi d^2 n$ also approaches zero.Consequently,the mean free path $\lambda$ approaches infinity $(\lambda 	o \infty)$.

If the diameter of a gas molecule is very small,what will be the mean free path?

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