If an electron moves from an excited state to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The visible region corresponds to the Balmer series $(n_f = 2)$.For $n$ transitions resulting in $4$ lines in the Balmer series,the electron must

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) The visible region corresponds to the Balmer series $(n_f = 2)$.For $n$ transitions resulting in $4$ lines in the Balmer series,the electron must jump from $n_i = 6$ to $n_f = 2$ (since the number of lines $= n_i - n_f = 6 - 2 = 4$).The infrared $(IR)$ region includes the Paschen $(n_f = 3)$,Brackett $(n_f = 4)$,and Pfund $(n_f = 5)$ series.For transitions from $n_i = 6$ to lower energy levels:Paschen series $(n_f = 3)$: $6$ $\rightarrow 3, 5$ $\rightarrow 3, 4$ $\rightarrow 3$ ($3$ lines).Brackett series $(n_f = 4)$: $6$ $\rightarrow 4, 5$ $\rightarrow 4$ ($2$ lines).Pfund series $(n_f = 5)$: $6 \rightarrow 5$ ($1$ line).Total lines in the $IR$ region $= 3 + 2 + 1 = 6$.

If an electron moves from an excited state to the ground state in multiple steps in the hydrogen spectrum,and the number of lines in the visible region is $4$,then the number of lines in the infrared region is:

Similar Questions

If the energy of a photon with a frequency of $2 \times 10^{12} \ Hz$ is $E$,then the energy of a photon with a frequency of $4 \times 10^{12} \ Hz$ will be ....

For a lithium atom,what can be said about the angular momentum and energy values for the permitted orbit of its third electron?

The ionization energy of $He^+$ is $19.6 \times 10^{-18} \ J \ atom^{-1}$. What is the energy of the first stationary state $(n = 1)$ of $Li^{2+}$?

In the atomic spectrum of hydrogen,the series of lines observed in the visible region is:

The ratio of the radius of the first orbit in hydrogen to the radius of the first orbit in deuterium is .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module