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(A) The number of electrons that can be accommodated in a shell with principal quantum number $n$ is given by the formula $N = 2n^2$.For $n = 1$,$N_1

Vedclass · Accepted Answer

$60$

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(A) The number of electrons that can be accommodated in a shell with principal quantum number $n$ is given by the formula $N = 2n^2$.For $n = 1$,$N_1 = 2(1)^2 = 2$.For $n = 2$,$N_2 = 2(2)^2 = 8$.For $n = 3$,$N_3 = 2(3)^2 = 18$.For $n = 4$,$N_4 = 2(4)^2 = 32$.The total number of possible elements is the sum of the maximum number of electrons in these shells:$N_{total} = N_1 + N_2 + N_3 + N_4 = 2 + 8 + 18 + 32 = 60$.Therefore,there would be $60$ possible elements.

If elements with principal quantum number $n > 4$ were not allowed in nature,then the number of possible elements would be

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