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(D) For a satellite of mass $m_s$ orbiting at a height $h$ from the surface of the Earth (mass $M_e$,radius $R_e$):$1$. Potential Energy $(P.E.)$ is g

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All of these

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(D) For a satellite of mass $m_s$ orbiting at a height $h$ from the surface of the Earth (mass $M_e$,radius $R_e$):$1$. Potential Energy $(P.E.)$ is given by $P.E. = -\frac{G M_e m_s}{R_e + h}$. As $h$ increases,the denominator increases,making the value less negative,which means the $P.E.$ increases.$2$. Kinetic Energy $(K.E.)$ is given by $K.E. = \frac{G M_e m_s}{2(R_e + h)}$. As $h$ increases,the denominator increases,so the $K.E.$ decreases.$3$. Total Energy $(T.E.)$ is given by $T.E. = P.E. + K.E. = -\frac{G M_e m_s}{2(R_e + h)}$. As $h$ increases,the value becomes less negative,which means the $T.E.$ increases.Therefore,all the given statements are correct. The correct option is $D$.

If the height of a satellite from the surface of the Earth is increased,then its

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