If in NH_3 formation N uses its pure atomic o | vedclass

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(D) If $N$ uses pure atomic orbitals $(2p_x, 2p_y, 2p_z)$ for bonding with $H$ atoms,the three $N-H$ bonds would be formed by the overlap of $N(2p)$ a

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Molecule will be $T$-shaped

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(D) If $N$ uses pure atomic orbitals $(2p_x, 2p_y, 2p_z)$ for bonding with $H$ atoms,the three $N-H$ bonds would be formed by the overlap of $N(2p)$ and $H(1s)$ orbitals. Since the $p$-orbitals are mutually perpendicular,the bond angles would be $90^{\circ}$. The lone pair would reside in the $2s$ orbital. However,the $N-H$ bonds formed by $p-s$ overlap would have identical strength. The geometry would be pyramidal,not $T$-shaped. Therefore,the statement that the molecule will be $T$-shaped is incorrect.

If in $NH_3$ formation $N$ uses its pure atomic orbitals,then the wrong statement is:

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