If in Delta XYZ,angle Y angle X angle Z,t | vedclass

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(B) In any triangle,the side opposite to the largest angle is the longest,and the side opposite to the smallest angle is the shortest.Given the angles

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$XY$

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(B) In any triangle,the side opposite to the largest angle is the longest,and the side opposite to the smallest angle is the shortest.Given the angles are $\angle Y > \angle X > \angle Z$.The side opposite to $\angle Y$ is $XZ$.The side opposite to $\angle X$ is $YZ$.The side opposite to $\angle Z$ is $XY$.Since $\angle Z$ is the smallest angle,the side opposite to it,which is $XY$,must be the smallest side of the triangle.

If in $\Delta XYZ$,$\angle Y > \angle X > \angle Z$,then find the smallest side of the triangle.

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