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(C) The circuit shown is a parallel combination of a diode $D$ and the output terminals. During the positive half-cycle of the input signal,the diode

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(C) The circuit shown is a parallel combination of a diode $D$ and the output terminals. During the positive half-cycle of the input signal,the diode $D$ is forward-biased $(FB)$. An ideal diode in forward bias acts as a short circuit,meaning the potential difference across it is $0 \ V$. Thus,the output voltage $V_0$ becomes $0 \ V$. During the negative half-cycle of the input signal,the diode $D$ is reverse-biased $(RB)$. An ideal diode in reverse bias acts as an open circuit,meaning no current flows through it. Thus,the entire input voltage appears across the output terminals. Therefore,the output voltage $V_0$ follows the input signal,which is $-5 \ V$ at its peak. Combining these,the output is a half-wave rectified signal showing only the negative half-cycle with a peak of $-5 \ V$.

If in a $p-n$ junction,a sinusoidal input signal is applied at $A$ as shown,then the output voltage $V_0$ will be:

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