If in a mineral 1000 tetrahedral basic unit o | vedclass

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(D) In a chain silicate,each $SiO_4^{4-}$ tetrahedron shares two oxygen atoms with other tetrahedra. For a chain consisting of $n$ units,the general f

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$Si_{1000}O_{3001}^{-2002}$

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(D) In a chain silicate,each $SiO_4^{4-}$ tetrahedron shares two oxygen atoms with other tetrahedra. For a chain consisting of $n$ units,the general formula for the silicate anion is $(SiO_3)_n^{2n-}$. Given $n = 1000$,the formula becomes $Si_{1000}O_{3000}^{2000-}$. However,the terminal oxygen atoms in the chain are not shared,meaning each end unit has one additional oxygen atom and carries an extra negative charge. For a linear chain of $n$ units,the formula is $(Si_nO_{3n+1})^{(2n+2)-}$. Substituting $n = 1000$: $Si_{1000}O_{3(1000)+1}^{(2(1000)+2)-} = Si_{1000}O_{3001}^{2002-}$. Thus,the correct option is $D$.

If in a mineral $1000$ tetrahedral basic unit of silicates are arranged in a chain,then what will be the formula of the anion of that mineral?

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