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(A) For a moderately asymmetrical (skewed) distribution,the empirical relationship between mean,median,and mode is given by:Mode = $3 	imes 	ext{med

Vedclass · Accepted Answer

$8 \lambda$

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(A) For a moderately asymmetrical (skewed) distribution,the empirical relationship between mean,median,and mode is given by:Mode = $3 	imes 	ext{median} - 2 	imes 	ext{mean}$Given:Mode = $6 \lambda$Mean = $9 \lambda$Substituting these values into the formula:$6 \lambda = 3 	imes 	ext{median} - 2 	imes (9 \lambda)$$6 \lambda = 3 	imes 	ext{median} - 18 \lambda$$3 	imes 	ext{median} = 6 \lambda + 18 \lambda$$3 	imes 	ext{median} = 24 \lambda$Median = $\frac{24 \lambda}{3} = 8 \lambda$

Class	$0-6$	$6-12$	$12-18$	$18-24$	$24-30$
Frequency	$a$	$b$	$12$	$9$	$5$

If in a moderately asymmetrical distribution,the mode and mean of the data are $6 \lambda$ and $9 \lambda$ respectively,then the median is:

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