If in the circuit,power dissipation is 150, W | vedclass

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(B) The circuit consists of two resistors $R$ and $2\,\Omega$ connected in parallel across a voltage source of $15\, V$.The equivalent resistance $R_{

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$6$

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(B) The circuit consists of two resistors $R$ and $2\,\Omega$ connected in parallel across a voltage source of $15\, V$.The equivalent resistance $R_{eq}$ of the parallel combination is given by:$R_{eq} = \frac{R 	imes 2}{R + 2} = \frac{2R}{R + 2}$The power dissipation $P$ in the circuit is given by the formula $P = \frac{V^2}{R_{eq}}$.Given $P = 150\, W$ and $V = 15\, V$,we have:$150 = \frac{15^2}{R_{eq}} = \frac{225}{R_{eq}}$$R_{eq} = \frac{225}{150} = 1.5\,\Omega$Now,equate the two expressions for $R_{eq}$:$1.5 = \frac{2R}{R + 2}$$1.5(R + 2) = 2R$$1.5R + 3 = 2R$$0.5R = 3$$R = \frac{3}{0.5} = 6\,\Omega$Therefore,the value of $R$ is $6\,\Omega$.

If in the circuit,power dissipation is $150\, W$,then $R$ is ............... $\Omega$.

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