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(A) The effective acceleration due to gravity $g'$ at a latitude $\lambda$ is given by the formula: $g' = g - \omega^2 R \cos^2 \lambda$. At the equat

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Decreases

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(A) The effective acceleration due to gravity $g'$ at a latitude $\lambda$ is given by the formula: $g' = g - \omega^2 R \cos^2 \lambda$. At the equator,the latitude $\lambda = 0^\circ$,so $\cos 0^\circ = 1$. Thus,the effective acceleration due to gravity at the equator is $g' = g - \omega^2 R$. Here,$\omega$ is the angular velocity of the Earth's rotation and $R$ is the radius of the Earth. If the spinning motion (angular velocity $\omega$) of the Earth increases,the term $\omega^2 R$ increases. Since $g'$ is calculated by subtracting this term from the constant $g$,an increase in $\omega$ leads to a decrease in $g'$. Since the weight of a body is $W = mg'$,a decrease in $g'$ results in a decrease in the weight of the body at the equator.

If it is assumed that the spinning motion of the Earth increases,then the weight of a body on the equator

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