If Mohan has 3 tickets of a lottery containin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Total number of tickets $= 3 + 9 = 12$. Mohan selects $3$ tickets out of $12$. The total number of ways to select $3$ tickets is ${}^{12}C_3 = \fr

Vedclass · Accepted Answer

$\frac{34}{55}$

Vedclass · Answer

(A) Total number of tickets $= 3 + 9 = 12$. Mohan selects $3$ tickets out of $12$. The total number of ways to select $3$ tickets is ${}^{12}C_3 = \frac{12 	imes 11 	imes 10}{3 	imes 2 	imes 1} = 220$. Mohan wins at least one prize if he does not get all $3$ blanks. The number of ways to select $3$ blanks out of $9$ is ${}^9C_3 = \frac{9 	imes 8 	imes 7}{3 	imes 2 	imes 1} = 84$. The probability of getting no prize is $P(	ext{no prize}) = \frac{84}{220} = \frac{21}{55}$. The probability of winning at least one prize is $1 - P(	ext{no prize}) = 1 - \frac{21}{55} = \frac{34}{55}$.

If Mohan has $3$ tickets of a lottery containing $3$ prizes and $9$ blanks,then his chance of winning at least one prize is

Similar Questions

Two numbers are selected at random from the numbers $1, 2, \dots, n$. The probability that the difference between the first and second number is not less than $m$ (where $0 < m < n$) is

$A$ bag contains $12$ pairs of socks. If $4$ socks are picked up at random,the probability that there is at least one pair is equal to

$A$ bag contains $8$ red and $7$ black balls. Two balls are drawn at random. The probability that both the balls are of the same colour is

Two cards are drawn at random from a well-shuffled pack of $52$ cards. Find the probability that one card is a prime number and the other is a multiple of $5$.

Two points are randomly chosen on the circumference of a circle of radius $r$. The probability that the distance between the two points is at least $r$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module