If on heating a liquid through 80^{circ}C,the | vedclass

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(A) The coefficient of apparent expansion $\gamma_{	ext{app}}$ is defined by the formula:$\gamma_{	ext{app}} = \frac{	ext{Mass expelled}}{	ext{Mas

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$1.25 	imes 10^{-4} {^{\circ}C^{-1}}$

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(A) The coefficient of apparent expansion $\gamma_{	ext{app}}$ is defined by the formula:$\gamma_{	ext{app}} = \frac{	ext{Mass expelled}}{	ext{Mass remaining} 	imes \Delta T}$Given that the mass expelled is $(1/100)$ of the mass remaining,let the mass remaining be $m$. Then the mass expelled is $m/100$.The change in temperature $\Delta T = 80^{\circ}C$.Substituting these values into the formula:$\gamma_{	ext{app}} = \frac{m/100}{m 	imes 80} = \frac{1}{100 	imes 80} = \frac{1}{8000}$$\gamma_{	ext{app}} = 0.000125 = 1.25 	imes 10^{-4} {^{\circ}C^{-1}}$Thus,the correct option is $A$.

If on heating a liquid through $80^{\circ}C$,the mass expelled is $(1/100)^{th}$ of the mass remaining,the coefficient of apparent expansion of the liquid is:

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