If one number is 80 % of the other and the su | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the two numbers be $x$ and $y$.According to the problem,one number is $80 \%$ of the other:$y = \frac{80}{100} x = \frac{4}{5} x$This implies

Vedclass · Accepted Answer

$16, 20$

Vedclass · Answer

(C) Let the two numbers be $x$ and $y$.According to the problem,one number is $80 \%$ of the other:$y = \frac{80}{100} x = \frac{4}{5} x$This implies $\frac{x}{y} = \frac{5}{4}$. Let $x = 5k$ and $y = 4k$ for some constant $k$.The sum of their squares is given as $656$:$x^2 + y^2 = 656$$(5k)^2 + (4k)^2 = 656$$25k^2 + 16k^2 = 656$$41k^2 = 656$$k^2 = \frac{656}{41} = 16$$k = 4$Substituting the value of $k$ back into the expressions for $x$ and $y$:$x = 5 	imes 4 = 20$$y = 4 	imes 4 = 16$Thus,the numbers are $16$ and $20$.

If one number is $80 \%$ of the other and the sum of their squares is $656$,then the numbers are:

Similar Questions

The price of a house increases every year by $20 \%$. If the present price is $Rs \ 720000$,then what was its price (in $Rs$) $2$ years ago?

What is $15$ percent of $ 34$?

In an examination,there were $2000$ candidates,out of which $900$ candidates were boys and the rest were girls. If $32 \%$ of the boys and $38 \%$ of the girls passed,then the total percentage of failed candidates is:

If $35 \%$ of a number is $12$ less than $50 \%$ of that number,then the number is:

Two numbers are $10\%$ and $25\%$ lesser than a third number. By what percentage must the second number be increased to make it equal to the first number (in $\%$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module