(A) For a quadratic equation of the form $ax^{2}+bx+c=0$,the sum of the roots is given by $\alpha+\beta = -\frac{b}{a}$.Here,$a=1$,$b=4$,and $c=m$.Giv

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) For a quadratic equation of the form $ax^{2}+bx+c=0$,the sum of the roots is given by $\alpha+\beta = -\frac{b}{a}$.Here,$a=1$,$b=4$,and $c=m$.Given that one root $\alpha = 2$,let the other root be $\beta$.Substituting the values into the sum formula: $2 + \beta = -\frac{4}{1}$.$2 + \beta = -4$.$\beta = -4 - 2$.$\beta = -6$.Therefore,the other root is $-6$.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

Easy

If one of the roots of quadratic equation $x^{2}+4x+m=0$ is $2$,then the other root is .... .

A
$-6$
B
$6$
C
$4$
D
$3$

Explore More

Browse All

Question Bank

All Subjects

Class 10 Questions

Class 10

Mathematics Questions

Chapter

Quadratic Equations

Subtopic

Mix Examples - Quadratic Equations

The solution set of $x^{2}+5x+6=0$ is $\ldots \ldots \ldots \ldots.$

Easy

View Solution

If the roots of the following quadratic equation exist,find them by the method of completing the square: $(2x + 1) - \frac{4}{(2x + 1)} - 3 = 0$.

Medium

View Solution

If $1$ is the solution of a quadratic equation $3x^{2}-kx+2=0$,then $k=\ldots$

Easy

View Solution

Find the roots of the quadratic equation by using the quadratic formula:
$\frac{1}{2} x^{2}-\sqrt{11} x+1=0$

Medium

View Solution

If $\frac{1}{2}$ is a root of the equation $x^{2}+kx-\frac{5}{4}=0$,then the value of $k$ is

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

If one of the roots of quadratic equation $x^{2}+4x+m=0$ is $2$,then the other root is .... .

Similar Questions

The solution set of $x^{2}+5x+6=0$ is $\ldots \ldots \ldots \ldots.$

If the roots of the following quadratic equation exist,find them by the method of completing the square: $(2x + 1) - \frac{4}{(2x + 1)} - 3 = 0$.

If $1$ is the solution of a quadratic equation $3x^{2}-kx+2=0$,then $k=\ldots$

Find the roots of the quadratic equation by using the quadratic formula:$\frac{1}{2} x^{2}-\sqrt{11} x+1=0$

If $\frac{1}{2}$ is a root of the equation $x^{2}+kx-\frac{5}{4}=0$,then the value of $k$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Find the roots of the quadratic equation by using the quadratic formula:
$\frac{1}{2} x^{2}-\sqrt{11} x+1=0$