If osmotic pressure of a solution is 2 atm a | vedclass

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(D) The osmotic pressure $(\pi)$ of a solution is given by the formula $\pi = CRT$,where $C$ is the molar concentration,$R$ is the gas constant,and $T

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$4$

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(D) The osmotic pressure $(\pi)$ of a solution is given by the formula $\pi = CRT$,where $C$ is the molar concentration,$R$ is the gas constant,and $T$ is the temperature in Kelvin.Since $C$ and $R$ are constant,$\pi \propto T$.Given: $\pi_1 = 2 \ atm$ at $T_1 = 273 \ K$.We need to find $\pi_2$ at $T_2 = 546 \ K$.Using the relation $\frac{\pi_1}{T_1} = \frac{\pi_2}{T_2}$:$\frac{2}{273} = \frac{\pi_2}{546}$.$\pi_2 = 2 	imes \frac{546}{273} = 2 	imes 2 = 4 \ atm$.

If osmotic pressure of a solution is $2 \ atm$ at $273 \ K$,then at $546 \ K$,the osmotic pressure is ........... $atm.$

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