(C) The representative elements where the period number equals the group number are $H$ ($1s^1$,Period $1$,Group $1$) and $Be$ ($1s^2 2s^2$,Period $2$

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The possible value of magnetic quantum number is $1$

(C) The representative elements where the period number equals the group number are $H$ ($1s^1$,Period $1$,Group $1$) and $Be$ ($1s^2 2s^2$,Period $2$,Group $2$).For $H$ $(1s^1)$: Principal quantum number $n = 1$,Azimuthal quantum number $l = 0$,Magnetic quantum number $m_l = 0$. It is paramagnetic.For $Be$ $(1s^2 2s^2)$: Principal quantum number $n = 2$,Azimuthal quantum number $l = 0$,Magnetic quantum number $m_l = 0$. It is diamagnetic.In both cases,the magnetic quantum number $m_l$ is $0$,not $1$. Therefore,statement $(c)$ is incorrect.

Class 11 Chemistry Classification of Elements and Periodicity in Properties Mix Examples - Classification of Elements and Periodicity in Properties

Medium

If the period number and group number of any representative element are the same,then which of the following statements is incorrect regarding such type of element in its ground state? (Period number and group number are according to the modern form of the periodic table)

A
The possible value of principal quantum number is $2$
B
The possible value of azimuthal quantum number is zero
C
The possible value of magnetic quantum number is $1$
D
The species could be paramagnetic

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Class 11

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Chapter

Classification of Elements and Periodicity in Properties

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Mix Examples - Classification of Elements and Periodicity in Properties

Consider the following orders :-
$(I)$ $Li > Na$ (Reducing nature)
$(II)$ $BF_3 > BCl_3 > BBr_3 > BI_3$ (Rate of hydrolysis)
$(III)$ $B > C > N > O > F$ ($1^{st}$ ionization energy)
$(IV)$ $CCl_4 > SiCl_4$ (Boiling point)
The $CORRECT$ order$(s)$ are :-

Difficult

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Match the Column $I$ with Column $II$ and select the correct answer using the given codes.
Column $I$ (Element types) Column $II$ (Electronic configuration)
$A$. Inert-gas elements $1. (n-1)d^{1-10} ns^{1-2}$
$B$. Transition elements $2. ns^2 np^6$
$C$. Inner-transition elements $3. (n-2)f^{1-14} (n-1)s^2 p^6 d^{0-1} ns^2$

Column $I$ (Element types)	Column $II$ (Electronic configuration)
$A$. Inert-gas elements	$1. (n-1)d^{1-10} ns^{1-2}$
$B$. Transition elements	$2. ns^2 np^6$
$C$. Inner-transition elements	$3. (n-2)f^{1-14} (n-1)s^2 p^6 d^{0-1} ns^2$

Difficult

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Match the items in List-$A$ with the items in List-$B$.

List-$A$ List-$B$

$(1)$ $He$ $(A)$ High electron gain enthalpy

$(2)$ $Cl$ $(B)$ Electropositive element

$(3)$ $Ca$ $(C)$ Strong reducing agent

$(4)$ $Li$ $(D)$ High ionization enthalpy

Easy

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Which of the following statements are correct?
$(i)$ First ionisation enthalpy of $He < $ Second ionisation enthalpy of $Li$.
$(ii)$ $Li$ has the highest second ionisation enthalpy.
$(iii)$ All $d$-block elements are transition elements.
$(iv)$ The only alphabet not found in the periodic table is the letter '$J$'.
$(v)$ Francium concentration is $\sim 10^{-18} \ ppm$ on Earth.

DifficultTS EAMCET 2018

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Which of the following orders is incorrect?

Medium

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List-$A$	List-$B$
$(1)$ $He$	$(A)$ High electron gain enthalpy
$(2)$ $Cl$	$(B)$ Electropositive element
$(3)$ $Ca$	$(C)$ Strong reducing agent
$(4)$ $Li$	$(D)$ High ionization enthalpy

If the period number and group number of any representative element are the same,then which of the following statements is incorrect regarding such type of element in its ground state? (Period number and group number are according to the modern form of the periodic table)

Similar Questions

Consider the following orders :-$(I)$ $Li > Na$ (Reducing nature)$(II)$ $BF_3 > BCl_3 > BBr_3 > BI_3$ (Rate of hydrolysis)$(III)$ $B > C > N > O > F$ ($1^{st}$ ionization energy)$(IV)$ $CCl_4 > SiCl_4$ (Boiling point)The $CORRECT$ order$(s)$ are :-

Match the items in List-$A$ with the items in List-$B$. List-$A$ List-$B$ $(1)$ $He$ $(A)$ High electron gain enthalpy $(2)$ $Cl$ $(B)$ Electropositive element $(3)$ $Ca$ $(C)$ Strong reducing agent $(4)$ $Li$ $(D)$ High ionization enthalpy

Which of the following orders is incorrect?

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Consider the following orders :-
$(I)$ $Li > Na$ (Reducing nature)
$(II)$ $BF_3 > BCl_3 > BBr_3 > BI_3$ (Rate of hydrolysis)
$(III)$ $B > C > N > O > F$ ($1^{st}$ ionization energy)
$(IV)$ $CCl_4 > SiCl_4$ (Boiling point)
The $CORRECT$ order$(s)$ are :-

Match the items in List-$A$ with the items in List-$B$.

List-$A$ List-$B$

$(1)$ $He$ $(A)$ High electron gain enthalpy

$(2)$ $Cl$ $(B)$ Electropositive element

$(3)$ $Ca$ $(C)$ Strong reducing agent

$(4)$ $Li$ $(D)$ High ionization enthalpy