If potential $V = 100 \pm 0.5\,V$ and current $I = 10 \pm 0.2\,A$ are given,what will be the value of resistance?

$A$ physical quantity $P$ is related to four observables $a, b, c$ and $d$ as follows: $P = \frac{a^3 b^2}{\sqrt{c} d}$. The percentage errors of measurement in $a, b, c$ and $d$ are $1 \%, 3 \%, 4 \%$ and $2 \%$ respectively. What is the percentage error in the quantity $P$? If the value of $P$ calculated using the above relation turns out to be $3.763$,to what value should you round off the result?

The percentage error in the measurement of mass and speed of a particular body is $3 \%$ and $4 \%$ respectively. The percentage error in the measurement of kinetic energy is (in $\%$)

Two resistances are given as $R_1 = (10 \pm 0.5) \ \Omega$ and $R_2 = (15 \pm 0.5) \ \Omega$. The percentage error in the measurement of equivalent resistance when they are connected in parallel is (in $\%$)

Quantity $Z$ varies with $x$ and $y$ according to the equation $Z = x^2y - xy^2$,where $x = 3.0 \pm 0.1$ and $y = 2.0 \pm 0.1$. The value of $Z$ is:

In an experiment for the measurement of $g$ using a simple pendulum,the time period was measured with an accuracy of $0.2 \%$ while the length was measured with an accuracy of $0.5 \%$. The percentage accuracy in the value of $g$ thus obtained is: (in $\%$)