If power dissipated in the 9 ,Omega resistor | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The power dissipated in the $9 \,\Omega$ resistor is given by $P = I_1^2 R_1$. Given $P = 36 \,W$ and $R_1 = 9 \,\Omega$,we have $36 = I_1^2 	ime

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(C) The power dissipated in the $9 \,\Omega$ resistor is given by $P = I_1^2 R_1$. Given $P = 36 \,W$ and $R_1 = 9 \,\Omega$,we have $36 = I_1^2 	imes 9$,which gives $I_1^2 = 4$,so $I_1 = 2 \,A$. Since the $9 \,\Omega$ and $6 \,\Omega$ resistors are connected in parallel,the potential difference across them is the same. Let $V_p$ be the potential difference across the parallel combination. Then $V_p = I_1 R_1 = 2 \,A 	imes 9 \,\Omega = 18 \,V$. The current through the $6 \,\Omega$ resistor is $I_2 = \frac{V_p}{R_2} = \frac{18 \,V}{6 \,\Omega} = 3 \,A$. The total current $I$ flowing through the $2 \,\Omega$ resistor is $I = I_1 + I_2 = 2 \,A + 3 \,A = 5 \,A$. The potential difference across the $2 \,\Omega$ resistor is $V_{2\Omega} = I 	imes 2 \,\Omega = 5 \,A 	imes 2 \,\Omega = 10 \,V$.

If power dissipated in the $9 \,\Omega$ resistor in the circuit shown is $36 \,W$,the potential difference across the $2 \,\Omega$ resistor is .......... $V$

Similar Questions

The storage battery of a car has an $emf$ of $12\; V$. If the internal resistance of the battery is $0.4\; \Omega,$ what is the maximum current (in $A$) that can be drawn from the battery?

The terminal voltage of the battery, whose emf is $10 \, V$ and internal resistance is $1 \, \Omega$, when connected through an external resistance of $4 \, \Omega$ as shown in the figure is: (in $V$)

The figure shows a network of resistances in which the point $A$ is earthed. The current through the $3\,\Omega$ resistor is

Two long coaxial and conducting cylinders of radius $a$ and $b$ are separated by a material of conductivity $\sigma$ and a constant potential difference $V$ is maintained between them by a battery. Then the current per unit length of the cylinder flowing from one cylinder to the other is -

$A$ bulb rated at $(100\,W, 200\,V)$ is used on a $100\,V$ line. The current in the bulb is

Vedclass Test Series

Exam Paper Generator

Online Exam Module