If the power dissipated in the circuit is 150 | vedclass

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(B) The circuit consists of two resistors $R$ connected in parallel across a voltage source of $V = 15\,V$.The total power dissipated in the circuit i

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$3$

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(B) The circuit consists of two resistors $R$ connected in parallel across a voltage source of $V = 15\,V$.The total power dissipated in the circuit is $P_{total} = 150\,W$.Since the resistors are in parallel,the voltage across each resistor is the same,$V = 15\,V$.The power dissipated by each resistor is $P = \frac{V^2}{R}$.The total power is the sum of the power dissipated by each resistor:$P_{total} = P_1 + P_2 = \frac{V^2}{R} + \frac{V^2}{R} = \frac{2V^2}{R}$.Substituting the given values:$150 = \frac{2 	imes (15)^2}{R}$$150 = \frac{2 	imes 225}{R}$$150 = \frac{450}{R}$$R = \frac{450}{150} = 3\,\Omega$.

If the power dissipated in the circuit is $150\,W,$ then the value of $R$ is ............... $\Omega$.

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