If the rate of diffusion of gas A is 5 times | vedclass

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Question

(A) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the density $d$ of the gas: $r \p

Vedclass · Accepted Answer

$0.04$

Vedclass · Answer

(A) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the density $d$ of the gas: $r \propto \frac{1}{\sqrt{d}}$.Therefore,$\frac{r_A}{r_B} = \sqrt{\frac{d_B}{d_A}}$.Given that $r_A = 5r_B$,we have $\frac{r_A}{r_B} = 5$.Substituting this into the equation: $5 = \sqrt{\frac{d_B}{d_A}}$.Squaring both sides: $25 = \frac{d_B}{d_A}$.Thus,the ratio of the density of $A$ to the density of $B$ is $\frac{d_A}{d_B} = \frac{1}{25} = 0.04$.

If the rate of diffusion of gas $A$ is $5$ times that of gas $B$,what will be the ratio of the density of $A$ to the density of $B$?

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