If somatic cells of a human male contain a si | vedclass

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(B) The number of Barr bodies in a cell is calculated by the formula $n - 1$,where $n$ is the number of $X$ chromosomes.In a normal human male $(46, X

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$XXY$

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(B) The number of Barr bodies in a cell is calculated by the formula $n - 1$,where $n$ is the number of $X$ chromosomes.In a normal human male $(46, XY)$,there is only one $X$ chromosome,so the number of Barr bodies is $1 - 1 = 0$.If a male has one Barr body,the number of $X$ chromosomes must be $n = 1 + 1 = 2$.Therefore,the individual has two $X$ chromosomes and one $Y$ chromosome,resulting in the genotype $XXY$ (Klinefelter syndrome).

If somatic cells of a human male contain a single Barr body,the genetic composition of the person would be:

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