If 10 volumes of dihydrogen gas react with 5 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The balanced chemical equation for the reaction is:$2H_{2(g)} + O_{2(g)} \longrightarrow 2H_{2}O_{(g)}$According to Gay-Lussac's Law of Gaseous Vo

Vedclass · Accepted Answer

$10$ volumes

Vedclass · Answer

(B) The balanced chemical equation for the reaction is:$2H_{2(g)} + O_{2(g)} \longrightarrow 2H_{2}O_{(g)}$According to Gay-Lussac's Law of Gaseous Volumes, $2$ volumes of $H_{2}$ react with $1$ volume of $O_{2}$ to produce $2$ volumes of $H_{2}O$ vapour.Given $10$ volumes of $H_{2}$ and $5$ volumes of $O_{2}$, the ratio is $10:5$ or $2:1$, which matches the stoichiometric ratio.Therefore, $10$ volumes of $H_{2}$ will react completely with $5$ volumes of $O_{2}$ to produce $10$ volumes of water vapour.

If $10$ volumes of dihydrogen gas react with $5$ volumes of dioxygen gas, how many volumes of water vapour would be produced?

Similar Questions

The ammonia $(NH_{3})$ released on quantitative reaction of $0.6 \ g$ urea $(NH_{2}CONH_{2})$ with sodium hydroxide $(NaOH)$ can be neutralized by

What is the ratio of the active masses of $22 \ g$ $CO_2$,$3 \ g$ $H_2$,and $7 \ g$ $N_2$ in a gaseous mixture?

Concentrated sulfuric acid is $95\%$ by weight and its density is $1.8 \ g \ cm^{-3}$. What volume of concentrated acid in $cm^3$ is required to prepare $4 \ L$ of $0.4 \ M \ H_2SO_4$ solution (in $.7$)?

One mole of magnesium nitride on the reaction with an excess of water gives

What is the value of $w$ (mass of solute in grams) required to prepare a definite volume of a standard solution of known normality $(N)$?
[$N = \text{normality}$,$E = \text{equivalent weight}$,$V = \text{volume of solution in } mL$]

Vedclass Test Series

Exam Paper Generator

Online Exam Module