If 10 volumes of dihydrogen gas reacts with 5 | vedclass

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(B) The balanced chemical equation for the reaction is:$2 H_{2(g)} + O_{2(g)} \rightarrow 2 H_{2}O_{(g)}$According to Gay-Lussac's Law of Gaseous Volu

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$10$ volumes

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(B) The balanced chemical equation for the reaction is:$2 H_{2(g)} + O_{2(g)} \rightarrow 2 H_{2}O_{(g)}$According to Gay-Lussac's Law of Gaseous Volumes,gases react in simple ratios by volume at constant temperature and pressure.From the equation,$2$ volumes of $H_2$ react with $1$ volume of $O_2$ to produce $2$ volumes of $H_2O$ vapour.Given $10$ volumes of $H_2$ and $5$ volumes of $O_2$,the ratio is $10:5$,which is $2:1$.Since the reactants are in the exact stoichiometric ratio,$10$ volumes of $H_2$ will react completely with $5$ volumes of $O_2$ to produce $10$ volumes of water vapour.

If $10$ volumes of dihydrogen gas reacts with $5$ volumes of dioxygen gas,how many volumes of water vapour would be produced?

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