If the V_{rms} of a gas is (30R)^{1/2} at 27, | vedclass

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(C) The formula for root mean square velocity $(V_{rms})$ is given by $V_{rms} = \sqrt{\frac{3RT}{M}}$.Given $V_{rms} = (30R)^{1/2}$ and $T = 27\,^{\c

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$0.03$

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(C) The formula for root mean square velocity $(V_{rms})$ is given by $V_{rms} = \sqrt{\frac{3RT}{M}}$.Given $V_{rms} = (30R)^{1/2}$ and $T = 27\,^{\circ}C = 27 + 273 = 300 \ K$.Substituting the values into the formula: $(30R)^{1/2} = \sqrt{\frac{3RT}{M}}$.Squaring both sides: $30R = \frac{3RT}{M}$.$30 = \frac{3 	imes 300}{M}$.$30 = \frac{900}{M}$.$M = \frac{900}{30} = 30 \ g/mol$.To convert the molar mass into $kg/mol$,we divide by $1000$: $M = \frac{30}{1000} = 0.03 \ kg/mol$.

If the $V_{rms}$ of a gas is $(30R)^{1/2}$ at $27\,^{\circ}C,$ then calculate the molar mass of the gas in $kg/mol$.

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