If the {p^{th}} term of an A.P. is q and the | vedclass

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(B) Let the first term be $a$ and the common difference be $d$.Given that,the ${p^{th}}$ term is ${T_p} = a + (p - 1)d = q$ ..... $(i)$And the ${q^{th

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$p + q - r$

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(B) Let the first term be $a$ and the common difference be $d$.Given that,the ${p^{th}}$ term is ${T_p} = a + (p - 1)d = q$ ..... $(i)$And the ${q^{th}}$ term is ${T_q} = a + (q - 1)d = p$ ..... $(ii)$Subtracting equation $(ii)$ from $(i)$:$(a + (p - 1)d) - (a + (q - 1)d) = q - p$$(p - 1 - q + 1)d = -(p - q)$$(p - q)d = -(p - q)$$d = -1$Substituting $d = -1$ in equation $(i)$:$a + (p - 1)(-1) = q$$a - p + 1 = q$$a = p + q - 1$Now,the ${r^{th}}$ term is ${T_r} = a + (r - 1)d$${T_r} = (p + q - 1) + (r - 1)(-1)$${T_r} = p + q - 1 - r + 1$${T_r} = p + q - r$Thus,the ${r^{th}}$ term is $p + q - r$.

If the ${p^{th}}$ term of an $A.P.$ is $q$ and the ${q^{th}}$ term is $p$,then its ${r^{th}}$ term will be

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