If the $6^{th}$ term in $\left(\frac{2p}{3} + \frac{3q}{2}\right)^9$ is $ap^bq^c$,then $a, b$ and $c$ respectively are

  • A
    $189, 5, 4$
  • B
    $189, 4, 5$
  • C
    $212, 4, 5$
  • D
    $212, 5, 4$

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