If the amplification factor of a triode $(\mu)$ is $22$ and its plate resistance is $6600 \, \Omega$,then the mutual conductance of this valve in mho is:

  • A
    $\frac{1}{300}$
  • B
    $25 \times 10^{-2}$
  • C
    $2.5 \times 10^{-2}$
  • D
    $0.25 \times 10^{-2}$

Explore More

Similar Questions

The correct relation for a triode is

For a triode, ${r_p} = 10 \text{ k}\Omega$ and ${g_m} = 3 \text{ m}\mho$. If the load resistance is double the plate resistance, then the value of the voltage gain will be:

In a triode valve,the amplification factor is $20$ and the mutual conductance is $10^{-3} \text{ mho}$. The plate resistance is:

The current in a triode at anode potential $100 \, V$ and grid potential $-1.2 \, V$ is $7.5 \, mA$. If the grid potential is changed to $-2.2 \, V$, the current becomes $5.5 \, mA$. The value of transconductance $(g_m)$ will be .... $mili \, mho$.

The voltage gain of a triode depends upon

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo