If the angle 2theta is acute,then the acute a | vedclass

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(C) The equation of the pair of lines is $ax^2 + 2hxy + by^2 = 0$,where $a = \cos 	heta - \sin 	heta$,$h = \cos 	heta$,and $b = \cos 	heta + \sin

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$	heta$

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(C) The equation of the pair of lines is $ax^2 + 2hxy + by^2 = 0$,where $a = \cos 	heta - \sin 	heta$,$h = \cos 	heta$,and $b = \cos 	heta + \sin 	heta$.The formula for the acute angle $\phi$ between the lines is $	an \phi = \left| \frac{2\sqrt{h^2 - ab}}{a + b} ight|$.First,calculate $h^2 - ab = \cos^2 	heta - (\cos 	heta - \sin 	heta)(\cos 	heta + \sin 	heta) = \cos^2 	heta - (\cos^2 	heta - \sin^2 	heta) = \sin^2 	heta$.Next,calculate $a + b = (\cos 	heta - \sin 	heta) + (\cos 	heta + \sin 	heta) = 2\cos 	heta$.Substituting these into the formula: $	an \phi = \frac{2\sqrt{\sin^2 	heta}}{2\cos 	heta} = \frac{2\sin 	heta}{2\cos 	heta} = 	an 	heta$.Thus,$\phi = 	heta$.

If the angle $2\theta$ is acute,then the acute angle between the lines represented by $x^2(\cos \theta - \sin \theta) + 2xy \cos \theta + y^2(\cos \theta + \sin \theta) = 0$ is

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