If the angles between the sides of the triangle $ABC$ formed by $A(2,3,5)$,$B(-1,3,2)$ and $C(3,5,-2)$ are $\alpha, \beta$ and $\gamma$,then $\sin^2 \alpha + \sin^2 \beta + \sin^2 \gamma = $

  • A
    $1$
  • B
    $2$
  • C
    $\frac{3}{2}$
  • D
    $\frac{1}{2}$

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