If the average number of neutrons liberated p | vedclass

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(C) Given: Power $P = 100 \, MW = 100 	imes 10^6 \, J/s$.Energy released per fission $E_f = 250 \, MeV = 250 	imes 1.6 	imes 10^{-13} \, J$.Average

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$6.25 	imes 10^{18}$

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(C) Given: Power $P = 100 \, MW = 100 	imes 10^6 \, J/s$.Energy released per fission $E_f = 250 \, MeV = 250 	imes 1.6 	imes 10^{-13} \, J$.Average neutrons per fission $n = 2.5$.First, calculate the number of fissions per second $(N/t)$:$N/t = P / E_f = (100 	imes 10^6) / (250 	imes 1.6 	imes 10^{-13})$$N/t = 10^8 / (400 	imes 10^{-13}) = 10^8 / (4 	imes 10^{-11}) = 0.25 	imes 10^{19} = 2.5 	imes 10^{18} \, 	ext{fissions/s}$.Now, calculate the total neutrons generated per second:$	ext{Neutrons/s} = (N/t) 	imes n = (2.5 	imes 10^{18}) 	imes 2.5 = 6.25 	imes 10^{18} \, 	ext{neutrons/s}$.

If the average number of neutrons liberated per fission is $2.5$ and energy released per fission is $250 \, MeV$, then the number of neutrons generated per second in a nuclear reactor of $100 \, MW$ will be:

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