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(B) The total number of ways to arrange $6$ examination papers is $6! = 720$.To find the number of arrangements where the best and the worst paper app

Vedclass · Accepted Answer

$480$

Vedclass · Answer

(B) The total number of ways to arrange $6$ examination papers is $6! = 720$.To find the number of arrangements where the best and the worst paper appear together,we treat them as a single unit.This leaves us with $5$ units (the pair + $4$ other papers),which can be arranged in $5!$ ways.Within the pair,the two papers can be arranged in $2!$ ways.So,the number of arrangements where they appear together is $5! 	imes 2! = 120 	imes 2 = 240$.The number of ways they never appear together is the total arrangements minus the arrangements where they are together:$720 - 240 = 480$.

If the best and the worst paper never appear together,then in how many ways can six examination papers be arranged?

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