(A) The boiling point elevation constant $K_B$ is given by the formula: $K_B = \frac{R \cdot T_B^2 \cdot M}{1000 \cdot \Delta H_{vap}}$.Since the mole

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) The boiling point elevation constant $K_B$ is given by the formula: $K_B = \frac{R \cdot T_B^2 \cdot M}{1000 \cdot \Delta H_{vap}}$.Since the molecular weights $M$ are the same and $R$ is a constant,we have $K_B \propto \frac{T_B^2}{\Delta H_{vap}}$.Given $\frac{(T_B)_X}{(T_B)_Y} = \frac{2}{1}$ and $\frac{(\Delta H)_X}{(\Delta H)_Y} = \frac{1}{2}$.Therefore,$\frac{(K_B)_X}{(K_B)_Y} = \left( \frac{(T_B)_X}{(T_B)_Y} \right)^2 \times \frac{(\Delta H)_Y}{(\Delta H)_X}$.Substituting the values: $\frac{(K_B)_X}{(K_B)_Y} = (2)^2 \times \left( \frac{2}{1} \right) = 4 \times 2 = 8$.Thus,$m = 8$.

Class 12 Chemistry Solutions Elevation of boiling point of the solvent

Medium

If the boiling points of two solvents $X$ and $Y$ (having same molecular weights) are in the ratio $2 : 1$ and their enthalpies of vaporization are in the ratio $1 : 2$,then the boiling point elevation constant of $X$ is $\underline{ m }$ times the boiling point elevation constant of $Y$. The value of $m$ is $.....$. (Nearest integer)

JEE MAIN 2023 All JEE MAIN

A
$8$
B
$6$
C
$4$
D
$2$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Solutions

Subtopic

Elevation of boiling point of the solvent

Previous Year

JEE MAIN 2023 Paper All JEE MAIN years →

The elevation in boiling point of a solution containing $1.8 \ g$ of glucose in $100 \ g$ of solvent is $0.1^{\circ}C$. The value of $K_b$ for the solvent is ........ $\frac{K}{m}$.

Medium

View Solution

$1 \ g$ of non-volatile non-electrolyte solute is dissolved in $100 \ g$ of two different solvents $A$ and $B$ whose ebullioscopic constants are in the ratio of $1 : 5$. The ratio of the elevation in their boiling points,$\frac{\Delta T_b (A)}{\Delta T_b (B)}$ is

DifficultJEE MAIN 2019

View Solution

$A$ solution is prepared by dissolving a $2.5 \ g$ sample of an unknown compound in $34 \ g$ of benzene,$C_6H_6$. The solution boils at $1.38 \ ^\circ C$ higher than pure benzene. Which expression gives the molar mass of the unknown compound? $K_b$ of $C_6H_6$ is $2.53 \ ^\circ C \ m^{-1}$.

Difficult

View Solution

$5 \text{ g}$ of urea is dissolved in $100 \text{ g}$ of water. Find the amount of glucose to be dissolved in $120 \text{ g}$ of water so that the boiling points of both solutions are the same. [Molar mass of urea $= 60 \text{ g mol}^{-1}$, Molar mass of glucose $= 180 \text{ g mol}^{-1}$] (in $\text{ g}$)

DifficultMHT CET 2026

View Solution

Calculate the boiling point elevation of a solution if $15 \ g$ of urea is dissolved in $1000 \ g$ of water. $\left[K_{b} \text{ for water} = 0.52 \ K \ kg \ mol^{-1}; \text{ molar mass of urea} = 60 \ g \ mol^{-1}\right]$ (in $K$)

EasyMHT CET 2025

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

The elevation in boiling point of a solution containing $1.8 \ g$ of glucose in $100 \ g$ of solvent is $0.1^{\circ}C$. The value of $K_b$ for the solvent is ........ $\frac{K}{m}$.

$1 \ g$ of non-volatile non-electrolyte solute is dissolved in $100 \ g$ of two different solvents $A$ and $B$ whose ebullioscopic constants are in the ratio of $1 : 5$. The ratio of the elevation in their boiling points,$\frac{\Delta T_b (A)}{\Delta T_b (B)}$ is

$A$ solution is prepared by dissolving a $2.5 \ g$ sample of an unknown compound in $34 \ g$ of benzene,$C_6H_6$. The solution boils at $1.38 \ ^\circ C$ higher than pure benzene. Which expression gives the molar mass of the unknown compound? $K_b$ of $C_6H_6$ is $2.53 \ ^\circ C \ m^{-1}$.

Calculate the boiling point elevation of a solution if $15 \ g$ of urea is dissolved in $1000 \ g$ of water. $\left[K_{b} \text{ for water} = 0.52 \ K \ kg \ mol^{-1}; \text{ molar mass of urea} = 60 \ g \ mol^{-1}\right]$ (in $K$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module