If the bond length and dipole moment of a dia | vedclass

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(C) The experimental dipole moment $\mu_{exp} = 1.0 \ D = 1.0 	imes 10^{-18} \ esu \ cm$. The theoretical dipole moment $\mu_{theo} = q 	imes d$,whe

Vedclass · Accepted Answer

$16.66$

Vedclass · Answer

(C) The experimental dipole moment $\mu_{exp} = 1.0 \ D = 1.0 	imes 10^{-18} \ esu \ cm$. The theoretical dipole moment $\mu_{theo} = q 	imes d$,where $q = 4.8 	imes 10^{-10} \ esu$ (charge of an electron) and $d = 1.25 \ \mathring{A} = 1.25 	imes 10^{-8} \ cm$. $\mu_{theo} = 1.25 	imes 10^{-8} \ cm 	imes 4.8 	imes 10^{-10} \ esu = 6.0 	imes 10^{-18} \ esu \ cm = 6.0 \ D$. The per cent ionic character is given by $\frac{\mu_{exp}}{\mu_{theo}} 	imes 100$. $	ext{Per cent ionic character} = \frac{1.0}{6.0} 	imes 100 = 16.66 \%$.

If the bond length and dipole moment of a diatomic molecule are $1.25 \ \mathring{A}$ and $1.0 \ D$ respectively,what is the per cent ionic character of the bond?

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