If the breaking force for a given wire is $F$, and the thickness of the wire is doubled, then the breaking force will be:

  • A
    $6F$
  • B
    $4F$
  • C
    $8F$
  • D
    $F$

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One end of a steel wire is fixed to the ceiling of an elevator moving up with an acceleration $2 \ m/s^2$ and a load of $10 \ kg$ hangs from the other end. If the cross-section of the wire is $2 \ cm^2$, then the longitudinal strain in the wire will be ($g = 10 \ m/s^2$ and $Y = 2.0 \times 10^{11} \ N/m^2$).

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