If the coefficients $a$ and $b$ of a quadratic expression $x^2+ax+b$ are chosen from the sets $A=\{3, 4, 5\}$ and $B=\{1, 2, 3, 4\}$ respectively, then the probability that the equation $x^2+ax+b=0$ has real roots is

  • A
    $\frac{1}{6}$
  • B
    $\frac{5}{6}$
  • C
    $\frac{3}{4}$
  • D
    $\frac{7}{12}$

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