If the coordinates of the points A, B, and C | vedclass

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(D) The area of a triangle with vertices $(x_1, y_1), (x_2, y_2),$ and $(x_3, y_3)$ is given by the formula: $	ext{Area} = \frac{1}{2} |x_1(y_2 - y_3

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$7$

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(D) The area of a triangle with vertices $(x_1, y_1), (x_2, y_2),$ and $(x_3, y_3)$ is given by the formula: $	ext{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$Substituting the given coordinates $A(4, 4), B(3, -2),$ and $C(3, -16)$:$	ext{Area} = \frac{1}{2} |4(-2 - (-16)) + 3(-16 - 4) + 3(4 - (-2))|$$	ext{Area} = \frac{1}{2} |4(14) + 3(-20) + 3(6)|$$	ext{Area} = \frac{1}{2} |56 - 60 + 18|$$	ext{Area} = \frac{1}{2} |14| = 7$Thus,the area of the triangle $ABC$ is $7$ square units.

If the coordinates of the points $A, B,$ and $C$ are $(4, 4), (3, -2),$ and $(3, -16)$ respectively,then the area of the triangle $ABC$ is

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