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(D) The power dissipated in a resistor is given by the formula $P = I^2 R$, where $I$ is the current and $R$ is the resistance.Initially, let the curr

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$300$

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(D) The power dissipated in a resistor is given by the formula $P = I^2 R$, where $I$ is the current and $R$ is the resistance.Initially, let the current be $I_1 = I$ and the power be $P_1 = I^2 R$.When the current is increased by $100\%$, the new current $I_2$ becomes $I + 100\% 	ext{ of } I = I + I = 2I$.The new power dissipated $P_2$ is $P_2 = (I_2)^2 R = (2I)^2 R = 4I^2 R = 4P_1$.The increase in power is $P_2 - P_1 = 4P_1 - P_1 = 3P_1$.The percentage increase in power is given by $\frac{P_2 - P_1}{P_1} 	imes 100\% = \frac{3P_1}{P_1} 	imes 100\% = 300\%$.

If the current $I$ through a resistor is increased by $100\%$ (assume that temperature remains unchanged), the increase in power dissipated will be ........ $\%$

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