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(B) The self-inductance $L$ of a coil with $N$ turns is defined by the relation $N\phi = LI$,where $\phi$ is the magnetic flux through each turn.Thus,

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$\frac{N \phi I}{2}$

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(B) The self-inductance $L$ of a coil with $N$ turns is defined by the relation $N\phi = LI$,where $\phi$ is the magnetic flux through each turn.Thus,the inductance is $L = \frac{N\phi}{I}$.The magnetic energy $U$ stored in an inductor is given by the formula $U = \frac{1}{2}LI^2$.Substituting the expression for $L$ into the energy formula:$U = \frac{1}{2} \left( \frac{N\phi}{I} \right) I^2$.Simplifying this,we get $U = \frac{1}{2} N\phi I$ or $U = \frac{N\phi I}{2}$.

If the current of $I$ gives rise to a magnetic flux $\phi$ through a coil having $N$ turns,then the magnetic energy stored in the medium surrounding the coil is

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