If the diameter of a carbon atom is 0.15 ,nm, | vedclass

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(A) Length of the scale $= 20 \,cm = 20 	imes 10^{-2} \,m = 0.2 \,m$.Diameter of a carbon atom $= 0.15 \,nm = 0.15 	imes 10^{-9} \,m$.Number of carb

Vedclass · Accepted Answer

$1.33 	imes 10^9$

Vedclass · Answer

(A) Length of the scale $= 20 \,cm = 20 	imes 10^{-2} \,m = 0.2 \,m$.Diameter of a carbon atom $= 0.15 \,nm = 0.15 	imes 10^{-9} \,m$.Number of carbon atoms $= \frac{	ext{Total length}}{	ext{Diameter of one atom}}$.Number of carbon atoms $= \frac{0.2 \,m}{0.15 	imes 10^{-9} \,m} = \frac{0.2}{0.15} 	imes 10^9$.Number of carbon atoms $= 1.333... 	imes 10^9 \approx 1.33 	imes 10^9$.

If the diameter of a carbon atom is $0.15 \,nm$,calculate the number of carbon atoms which can be placed side by side in a straight line across the length of a scale of length $20 \,cm$.

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