If the dipole moments of H_2S,NH_3,NF_3,and B | vedclass

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Question

(A) The structure of a molecule is determined by its hybridization and the number of lone pairs on the central atom.$BF_3$ has $sp^2$ hybridization wi

Vedclass · Accepted Answer

$BF_3$

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(A) The structure of a molecule is determined by its hybridization and the number of lone pairs on the central atom.$BF_3$ has $sp^2$ hybridization with no lone pairs on the boron atom,resulting in a trigonal planar geometry.$NH_3$ and $NF_3$ have $sp^3$ hybridization with one lone pair,resulting in a trigonal pyramidal geometry.$H_2S$ has $sp^3$ hybridization with two lone pairs,resulting in a bent ($V$-shaped) geometry.Since $BF_3$ is the only molecule with a trigonal planar structure,the correct option is $A$.

List-$I$	List-$II$
$A. XeF_4$	$I. See-saw$
$B. SF_4$	$II. Square planar$
$C. NH_4^{+}$	$III. Bent T-shaped$
$D. BrF_3$	$IV. Tetrahedral$

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $NH_3$	$I$. Square pyramid
$B$. $BrF_5$	$II$. Tetrahedral
$C$. $PCl_5$	$III$. Trigonal pyramidal
$D$. $CH_4$	$IV$. Trigonal bipyramidal

If the dipole moments of $H_2S$,$NH_3$,$NF_3$,and $BF_3$ are $0.95 \ D$,$1.47 \ D$,$0.23 \ D$,and $0.0 \ D$ respectively,the molecule that has a trigonal planar structure is:

Similar Questions

In which of the following molecules are all bond lengths the same?

Match List-$I$ with List-$II$:
List-$I$ List-$II$
$A. XeF_4$ $I. See-saw$
$B. SF_4$ $II. Square planar$
$C. NH_4^{+}$ $III. Bent T-shaped$
$D. BrF_3$ $IV. Tetrahedral$

Choose the correct answer from the options given below:

Explain why $PCl_5$ is trigonal bipyramidal whereas $IF_5$ is square pyramidal.

Match List-$I$ with List-$II$:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $NH_3$ $I$. Square pyramid

$B$. $BrF_5$ $II$. Tetrahedral

$C$. $PCl_5$ $III$. Trigonal pyramidal

$D$. $CH_4$ $IV$. Trigonal bipyramidal

Choose the correct answer from the options below:

Which of the following is an incorrect statement about $PCl_5$?

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