If the distance between a point source and a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The intensity $I$ of light from a point source follows the inverse square law with respect to the distance $r$ from the source.Mathematically,$I \

Vedclass · Accepted Answer

One-fourth

Vedclass · Answer

(D) The intensity $I$ of light from a point source follows the inverse square law with respect to the distance $r$ from the source.Mathematically,$I \propto \frac{1}{r^2}$.If the initial distance is $r_1 = r$ and the final distance is $r_2 = 2r$,the new intensity $I'$ is given by:$I' \propto \frac{1}{(2r)^2} = \frac{1}{4r^2} = \frac{1}{4} I$.Therefore,the intensity becomes one-fourth of its original value.

If the distance between a point source and a screen is doubled,then the intensity of light on the screen will become:

Similar Questions

In the phenomenon of interference:

If the wavelength of light is $4000 \, Å$, then the number of waves in a length of $1 \, mm$ will be:

Interference cannot be observed in two sodium lamps of equal power because the two waves do not have a .....

Define constructive interference. $OR$ Define destructive interference.

Two monochromatic light waves of amplitudes $3A$ and $2A$ interfering at a point have a phase difference of $60^{\circ}$. The intensity at that point will be proportional to.......$A^2$

Vedclass Test Series

Exam Paper Generator

Online Exam Module