If the energies of two light radiations E_1 a | vedclass

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(B) According to Planck's quantum theory,the energy of a photon is given by the relation: $E = \frac{hc}{\lambda}$ This implies that energy is inverse

Vedclass · Accepted Answer

$4:1$

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(B) According to Planck's quantum theory,the energy of a photon is given by the relation: $E = \frac{hc}{\lambda}$ This implies that energy is inversely proportional to wavelength: $E \propto \frac{1}{\lambda} \Rightarrow \lambda \propto \frac{1}{E}$ Given the energies $E_1 = 25 \ eV$ and $E_2 = 100 \ eV$,the ratio of their wavelengths is: $\frac{\lambda_1}{\lambda_2} = \frac{E_2}{E_1}$ Substituting the given values: $\frac{\lambda_1}{\lambda_2} = \frac{100 \ eV}{25 \ eV} = \frac{4}{1}$ Therefore,the ratio $\lambda_1: \lambda_2$ is $4:1$.

If the energies of two light radiations $E_1$ and $E_2$ are $25 \ eV$ and $100 \ eV$ respectively,then their respective wavelengths $\lambda_1$ and $\lambda_2$ would be in the ratio $\lambda_1: \lambda_2=$

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