If the enthalpy and entropy change for a reaction at $298 \ K$ are $-145 \ kJ \ mol^{-1}$ and $-650 \ J \ K^{-1} \ mol^{-1}$ respectively,which one of the following statements is correct?
- A$\Delta G = -50 \ kJ \ mol^{-1}$,the reaction is spontaneous
- B$\Delta G = -48.7 \ kJ \ mol^{-1}$,the reaction is non-spontaneous
- C$\Delta G = +50 \ kJ \ mol^{-1}$,the reaction is spontaneous
- D$\Delta G = +48.7 \ kJ \ mol^{-1}$,the reaction is non-spontaneous
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Similar Questions
If for a certain reaction $\Delta_{r} H$ is $30 \; kJ \; mol^{-1}$ at $450 \; K$,the value of $\Delta_{r} S$ (in $J \; K^{-1} \; mol^{-1}$) for which the same reaction will be spontaneous at the same temperature is
MediumNEET 2020
View SolutionFor independent processes at $300 \ K$,determine the number of non-spontaneous processes from the following table:
Process $\Delta H \ (kJ \ mol^{-1})$ $\Delta S \ (J \ K^{-1} \ mol^{-1})$ $A$ $-25$ $-80$ $B$ $-22$ $40$ $C$ $25$ $-50$ $D$ $22$ $20$
| Process | $\Delta H \ (kJ \ mol^{-1})$ | $\Delta S \ (J \ K^{-1} \ mol^{-1})$ |
|---|---|---|
| $A$ | $-25$ | $-80$ |
| $B$ | $-22$ | $40$ |
| $C$ | $25$ | $-50$ |
| $D$ | $22$ | $20$ |
For the decomposition reaction of $N_2O_4$,$\Delta H = 58.04 \, kJ$ and $\Delta S = 176.7 \, J/K$. Calculate $\Delta G$ in $kJ$ at $T = 298 \, K$.
Medium
View SolutionCalculate the amount of work done during isothermal expansion of a gas from a volume of $4 \ dm^{3}$ to $6 \ dm^{3}$ against a constant external pressure of $3 \ atm$ (in $J$)?
At $273 \ K$ the maximum work done when pressure on $10 \ g$ of hydrogen is reduced from $10 \ atm$ to $1 \ atm$ under isothermal,reversible conditions is (Assume the gas behaves ideally) $(R=8.3 \ J \ K^{-1} \ mol^{-1})$
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